110333230130121 has 4 divisors (see below), whose sum is σ = 147110973506832. Its totient is φ = 73555486753412.

The previous prime is 110333230130089. The next prime is 110333230130129. The reversal of 110333230130121 is 121031032333011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 110333230130121 - 2⁵ = 110333230130089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110333230130091 and 110333230130100.

It is not an unprimeable number, because it can be changed into a prime (110333230130129) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18388871688351 + ... + 18388871688356.

It is an arithmetic number, because the mean of its divisors is an integer number (36777743376708).

Almost surely, 2^{110333230130121} is an apocalyptic number.

It is an amenable number.

110333230130121 is a deficient number, since it is larger than the sum of its proper divisors (36777743376711).

110333230130121 is an equidigital number, since it uses as much as digits as its factorization.

110333230130121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36777743376710.

The product of its (nonzero) digits is 972, while the sum is 24.

Adding to 110333230130121 its reverse (121031032333011), we get a palindrome (231364262463132).

The spelling of 110333230130121 in words is "one hundred ten trillion, three hundred thirty-three billion, two hundred thirty million, one hundred thirty thousand, one hundred twenty-one".