Base | Representation |
---|---|
bin | 10000000011100111110… |
… | …010001011110011001011 |
3 | 10220111001212100221011001 |
4 | 100003213302023303023 |
5 | 121034230440221303 |
6 | 2202521202115431 |
7 | 142501200654346 |
oct | 20034762136313 |
9 | 3814055327131 |
10 | 1103400320203 |
11 | 395a49795985 |
12 | 159a1a64bb77 |
13 | 800863b3a6c |
14 | 3b594d1945d |
15 | 1da7e26d31d |
hex | 100e7c8bccb |
1103400320203 has 2 divisors, whose sum is σ = 1103400320204. Its totient is φ = 1103400320202.
The previous prime is 1103400320189. The next prime is 1103400320233. The reversal of 1103400320203 is 3020230043011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1103400320203 - 213 = 1103400312011 is a prime.
It is a super-2 number, since 2×11034003202032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1103400320233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551700160101 + 551700160102.
It is an arithmetic number, because the mean of its divisors is an integer number (551700160102).
Almost surely, 21103400320203 is an apocalyptic number.
1103400320203 is a deficient number, since it is larger than the sum of its proper divisors (1).
1103400320203 is an equidigital number, since it uses as much as digits as its factorization.
1103400320203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 1103400320203 its reverse (3020230043011), we get a palindrome (4123630363214).
The spelling of 1103400320203 in words is "one trillion, one hundred three billion, four hundred million, three hundred twenty thousand, two hundred three".
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