Base | Representation |
---|---|
bin | 11001000101101010100001… |
… | …000000001110000001010011 |
3 | 112110200102212221221111112011 |
4 | 121011222201000032001103 |
5 | 103430304130210222233 |
6 | 1030401403545243351 |
7 | 32145555150466126 |
oct | 3105524100160123 |
9 | 473612787844464 |
10 | 110340411023443 |
11 | 321811184aa527 |
12 | 10460864493557 |
13 | 4975096383553 |
14 | 1d3670c0843bd |
15 | cb53199e80cd |
hex | 645aa100e053 |
110340411023443 has 2 divisors, whose sum is σ = 110340411023444. Its totient is φ = 110340411023442.
The previous prime is 110340411023407. The next prime is 110340411023449. The reversal of 110340411023443 is 344320114043011.
It is a strong prime.
It is an emirp because it is prime and its reverse (344320114043011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110340411023443 - 233 = 110331821088851 is a prime.
It is not a weakly prime, because it can be changed into another prime (110340411023449) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55170205511721 + 55170205511722.
It is an arithmetic number, because the mean of its divisors is an integer number (55170205511722).
Almost surely, 2110340411023443 is an apocalyptic number.
110340411023443 is a deficient number, since it is larger than the sum of its proper divisors (1).
110340411023443 is an equidigital number, since it uses as much as digits as its factorization.
110340411023443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 110340411023443 its reverse (344320114043011), we get a palindrome (454660525066454).
The spelling of 110340411023443 in words is "one hundred ten trillion, three hundred forty billion, four hundred eleven million, twenty-three thousand, four hundred forty-three".
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