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110341141033 is a prime number
BaseRepresentation
bin110011011000011011…
…0000011001000101001
3101112210212022201220011
41212300312003020221
53301434313003113
6122405013331521
710654233136504
oct1466066031051
9345725281804
10110341141033
1142882774452
1219475036ba1
13a5360a09c6
1454aa62613b
152d0c03163d
hex19b0d83229

110341141033 has 2 divisors, whose sum is σ = 110341141034. Its totient is φ = 110341141032.

The previous prime is 110341141003. The next prime is 110341141073. The reversal of 110341141033 is 330141143011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 81363569049 + 28977571984 = 285243^2 + 170228^2 .

It is an emirp because it is prime and its reverse (330141143011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110341141033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110341140995 and 110341141013.

It is not a weakly prime, because it can be changed into another prime (110341141003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55170570516 + 55170570517.

It is an arithmetic number, because the mean of its divisors is an integer number (55170570517).

Almost surely, 2110341141033 is an apocalyptic number.

It is an amenable number.

110341141033 is a deficient number, since it is larger than the sum of its proper divisors (1).

110341141033 is an equidigital number, since it uses as much as digits as its factorization.

110341141033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 110341141033 its reverse (330141143011), we get a palindrome (440482284044).

It can be divided in two parts, 110 and 341141033, that added together give a palindrome (341141143).

The spelling of 110341141033 in words is "one hundred ten billion, three hundred forty-one million, one hundred forty-one thousand, thirty-three".