Base | Representation |
---|---|
bin | 10100100100000100… |
… | …11100110010011111 |
3 | 1001111101210122222011 |
4 | 22102002130302133 |
5 | 140102223102320 |
6 | 5023254332051 |
7 | 540403610446 |
oct | 122202346237 |
9 | 31441718864 |
10 | 11040050335 |
11 | 4755903246 |
12 | 218135a027 |
13 | 106c30b082 |
14 | 76a337d5d |
15 | 44935105a |
hex | 29209cc9f |
11040050335 has 4 divisors (see below), whose sum is σ = 13248060408. Its totient is φ = 8832040264.
The previous prime is 11040050299. The next prime is 11040050353. The reversal of 11040050335 is 53305004011.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53305004011 = 7 ⋅7615000573.
It is a cyclic number.
It is not a de Polignac number, because 11040050335 - 27 = 11040050207 is a prime.
It is a super-2 number, since 2×110400503352 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1104005029 + ... + 1104005038.
It is an arithmetic number, because the mean of its divisors is an integer number (3312015102).
Almost surely, 211040050335 is an apocalyptic number.
11040050335 is a deficient number, since it is larger than the sum of its proper divisors (2208010073).
11040050335 is an equidigital number, since it uses as much as digits as its factorization.
11040050335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2208010072.
The product of its (nonzero) digits is 900, while the sum is 22.
Adding to 11040050335 its reverse (53305004011), we get a palindrome (64345054346).
The spelling of 11040050335 in words is "eleven billion, forty million, fifty thousand, three hundred thirty-five".
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