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11040125644553 is a prime number
BaseRepresentation
bin1010000010100111101011…
…0001000110111100001001
31110002102111100010121201212
42200221322301012330021
52421340134131111203
635251432543222505
72216423414424635
oct240517261067411
943072440117655
1011040125644553
113577100124625
1212a37978a7a35
136211055287b5
142a24b86cbdc5
151422a420e1d8
hexa0a7ac46f09

11040125644553 has 2 divisors, whose sum is σ = 11040125644554. Its totient is φ = 11040125644552.

The previous prime is 11040125644501. The next prime is 11040125644591. The reversal of 11040125644553 is 35544652104011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5848982630089 + 5191143014464 = 2418467^2 + 2278408^2 .

It is a cyclic number.

It is not a de Polignac number, because 11040125644553 - 210 = 11040125643529 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11040125644553.

It is not a weakly prime, because it can be changed into another prime (11040125644453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5520062822276 + 5520062822277.

It is an arithmetic number, because the mean of its divisors is an integer number (5520062822277).

Almost surely, 211040125644553 is an apocalyptic number.

It is an amenable number.

11040125644553 is a deficient number, since it is larger than the sum of its proper divisors (1).

11040125644553 is an equidigital number, since it uses as much as digits as its factorization.

11040125644553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288000, while the sum is 41.

Adding to 11040125644553 its reverse (35544652104011), we get a palindrome (46584777748564).

The spelling of 11040125644553 in words is "eleven trillion, forty billion, one hundred twenty-five million, six hundred forty-four thousand, five hundred fifty-three".