Base | Representation |
---|---|
bin | 1010000010100111101011… |
… | …0001000110111100001001 |
3 | 1110002102111100010121201212 |
4 | 2200221322301012330021 |
5 | 2421340134131111203 |
6 | 35251432543222505 |
7 | 2216423414424635 |
oct | 240517261067411 |
9 | 43072440117655 |
10 | 11040125644553 |
11 | 3577100124625 |
12 | 12a37978a7a35 |
13 | 6211055287b5 |
14 | 2a24b86cbdc5 |
15 | 1422a420e1d8 |
hex | a0a7ac46f09 |
11040125644553 has 2 divisors, whose sum is σ = 11040125644554. Its totient is φ = 11040125644552.
The previous prime is 11040125644501. The next prime is 11040125644591. The reversal of 11040125644553 is 35544652104011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5848982630089 + 5191143014464 = 2418467^2 + 2278408^2 .
It is a cyclic number.
It is not a de Polignac number, because 11040125644553 - 210 = 11040125643529 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11040125644553.
It is not a weakly prime, because it can be changed into another prime (11040125644453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5520062822276 + 5520062822277.
It is an arithmetic number, because the mean of its divisors is an integer number (5520062822277).
Almost surely, 211040125644553 is an apocalyptic number.
It is an amenable number.
11040125644553 is a deficient number, since it is larger than the sum of its proper divisors (1).
11040125644553 is an equidigital number, since it uses as much as digits as its factorization.
11040125644553 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288000, while the sum is 41.
Adding to 11040125644553 its reverse (35544652104011), we get a palindrome (46584777748564).
The spelling of 11040125644553 in words is "eleven trillion, forty billion, one hundred twenty-five million, six hundred forty-four thousand, five hundred fifty-three".
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