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1104013153 is a prime number
BaseRepresentation
bin100000111001101…
…1110011101100001
32211221101200100001
41001303132131201
54230111410103
6301314500001
736233646145
oct10163363541
92757350301
101104013153
11517206471
12269894601
13147957529
14a68a5225
1566dca01d
hex41cde761

1104013153 has 2 divisors, whose sum is σ = 1104013154. Its totient is φ = 1104013152.

The previous prime is 1104013103. The next prime is 1104013171. The reversal of 1104013153 is 3513104011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 905287744 + 198725409 = 30088^2 + 14097^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1104013153 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1104013153.

It is not a weakly prime, because it can be changed into another prime (1104013103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552006576 + 552006577.

It is an arithmetic number, because the mean of its divisors is an integer number (552006577).

Almost surely, 21104013153 is an apocalyptic number.

It is an amenable number.

1104013153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1104013153 is an equidigital number, since it uses as much as digits as its factorization.

1104013153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180, while the sum is 19.

The square root of 1104013153 is about 33226.6933804735. The cubic root of 1104013153 is about 1033.5339549305.

Adding to 1104013153 its reverse (3513104011), we get a palindrome (4617117164).

The spelling of 1104013153 in words is "one billion, one hundred four million, thirteen thousand, one hundred fifty-three".