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11040133054777 is a prime number
BaseRepresentation
bin1010000010100111101100…
…1101011000000100111001
31110002102111212002002122121
42200221323031120010321
52421340143030223102
635251433410121241
72216423534420041
oct240517315300471
943072455062577
1011040133054777
113577104325a82
1212a379a280221
13621106c21648
142a24b969a721
151422a4bc4b37
hexa0a7b358139

11040133054777 has 2 divisors, whose sum is σ = 11040133054778. Its totient is φ = 11040133054776.

The previous prime is 11040133054771. The next prime is 11040133054781. The reversal of 11040133054777 is 77745033104011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11033983201536 + 6149853241 = 3321744^2 + 78421^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11040133054777 is a prime.

It is not a weakly prime, because it can be changed into another prime (11040133054771) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5520066527388 + 5520066527389.

It is an arithmetic number, because the mean of its divisors is an integer number (5520066527389).

Almost surely, 211040133054777 is an apocalyptic number.

It is an amenable number.

11040133054777 is a deficient number, since it is larger than the sum of its proper divisors (1).

11040133054777 is an equidigital number, since it uses as much as digits as its factorization.

11040133054777 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 246960, while the sum is 43.

Adding to 11040133054777 its reverse (77745033104011), we get a palindrome (88785166158788).

The spelling of 11040133054777 in words is "eleven trillion, forty billion, one hundred thirty-three million, fifty-four thousand, seven hundred seventy-seven".