Base | Representation |
---|---|
bin | 110011011010001111… |
… | …0101111111101000001 |
3 | 101112222010002220111212 |
4 | 1212310132233331001 |
5 | 3302100422021032 |
6 | 122415033015505 |
7 | 10655603503106 |
oct | 1466436577501 |
9 | 345863086455 |
10 | 110402142017 |
11 | 42904149392 |
12 | 19491554595 |
13 | a54590b46b |
14 | 54b4784aad |
15 | 2d12580bb2 |
hex | 19b47aff41 |
110402142017 has 2 divisors, whose sum is σ = 110402142018. Its totient is φ = 110402142016.
The previous prime is 110402141959. The next prime is 110402142029. The reversal of 110402142017 is 710241204011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 86574823696 + 23827318321 = 294236^2 + 154361^2 .
It is a cyclic number.
It is not a de Polignac number, because 110402142017 - 212 = 110402137921 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 110402141983 and 110402142001.
It is not a weakly prime, because it can be changed into another prime (110402142517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55201071008 + 55201071009.
It is an arithmetic number, because the mean of its divisors is an integer number (55201071009).
Almost surely, 2110402142017 is an apocalyptic number.
It is an amenable number.
110402142017 is a deficient number, since it is larger than the sum of its proper divisors (1).
110402142017 is an equidigital number, since it uses as much as digits as its factorization.
110402142017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 448, while the sum is 23.
Adding to 110402142017 its reverse (710241204011), we get a palindrome (820643346028).
The spelling of 110402142017 in words is "one hundred ten billion, four hundred two million, one hundred forty-two thousand, seventeen".
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