Base | Representation |
---|---|
bin | 10000000100001101011… |
… | …001100110111110101001 |
3 | 10220112200211212201112101 |
4 | 100010031121212332221 |
5 | 121042024020142022 |
6 | 2203103544413401 |
7 | 142522633110463 |
oct | 20041531467651 |
9 | 3815624781471 |
10 | 1104031412137 |
11 | 396242a4a665 |
12 | 159b75a77261 |
13 | 80157077644 |
14 | 3b614a77133 |
15 | 1dab987d627 |
hex | 1010d666fa9 |
1104031412137 has 2 divisors, whose sum is σ = 1104031412138. Its totient is φ = 1104031412136.
The previous prime is 1104031412119. The next prime is 1104031412177. The reversal of 1104031412137 is 7312141304011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1102928441616 + 1102970521 = 1050204^2 + 33211^2 .
It is a cyclic number.
It is not a de Polignac number, because 1104031412137 - 219 = 1104030887849 is a prime.
It is not a weakly prime, because it can be changed into another prime (1104031412177) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552015706068 + 552015706069.
It is an arithmetic number, because the mean of its divisors is an integer number (552015706069).
Almost surely, 21104031412137 is an apocalyptic number.
It is an amenable number.
1104031412137 is a deficient number, since it is larger than the sum of its proper divisors (1).
1104031412137 is an equidigital number, since it uses as much as digits as its factorization.
1104031412137 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 28.
Adding to 1104031412137 its reverse (7312141304011), we get a palindrome (8416172716148).
The spelling of 1104031412137 in words is "one trillion, one hundred four billion, thirty-one million, four hundred twelve thousand, one hundred thirty-seven".
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