Base | Representation |
---|---|
bin | 110011011010010001… |
… | …0111111101100001111 |
3 | 101112222012012110022111 |
4 | 1212310202333230033 |
5 | 3302101213130210 |
6 | 122415112524451 |
7 | 10655616120112 |
oct | 1466442775417 |
9 | 345865173274 |
10 | 110403255055 |
11 | 42904839655 |
12 | 194919b0727 |
13 | a545c0ac72 |
14 | 54b4994579 |
15 | 2d1270088a |
hex | 19b48bfb0f |
110403255055 has 32 divisors (see below), whose sum is σ = 137737454400. Its totient is φ = 84851837952.
The previous prime is 110403255041. The next prime is 110403255073. The reversal of 110403255055 is 550552304011.
It is a cyclic number.
It is not a de Polignac number, because 110403255055 - 29 = 110403254543 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 25774944 + ... + 25779226.
It is an arithmetic number, because the mean of its divisors is an integer number (4304295450).
Almost surely, 2110403255055 is an apocalyptic number.
110403255055 is a deficient number, since it is larger than the sum of its proper divisors (27334199345).
110403255055 is a wasteful number, since it uses less digits than its factorization.
110403255055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5163.
The product of its (nonzero) digits is 15000, while the sum is 31.
Adding to 110403255055 its reverse (550552304011), we get a palindrome (660955559066).
The spelling of 110403255055 in words is "one hundred ten billion, four hundred three million, two hundred fifty-five thousand, fifty-five".
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