Base | Representation |
---|---|
bin | 110011011010010010… |
… | …1111000101011010001 |
3 | 101112222020121221200101 |
4 | 1212310211320223101 |
5 | 3302101411402003 |
6 | 122415141052401 |
7 | 10655625424126 |
oct | 1466445705321 |
9 | 345866557611 |
10 | 110404012753 |
11 | 42905206951 |
12 | 194920b7101 |
13 | a546114ac8 |
14 | 54b4b1074d |
15 | 2d1280011d |
hex | 19b4978ad1 |
110404012753 has 2 divisors, whose sum is σ = 110404012754. Its totient is φ = 110404012752.
The previous prime is 110404012673. The next prime is 110404012811. The reversal of 110404012753 is 357210404011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 59441853249 + 50962159504 = 243807^2 + 225748^2 .
It is a cyclic number.
It is not a de Polignac number, because 110404012753 - 225 = 110370458321 is a prime.
It is not a weakly prime, because it can be changed into another prime (110404016753) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55202006376 + 55202006377.
It is an arithmetic number, because the mean of its divisors is an integer number (55202006377).
Almost surely, 2110404012753 is an apocalyptic number.
It is an amenable number.
110404012753 is a deficient number, since it is larger than the sum of its proper divisors (1).
110404012753 is an equidigital number, since it uses as much as digits as its factorization.
110404012753 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3360, while the sum is 28.
Adding to 110404012753 its reverse (357210404011), we get a palindrome (467614416764).
The spelling of 110404012753 in words is "one hundred ten billion, four hundred four million, twelve thousand, seven hundred fifty-three".
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