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11041004013 = 313476023461
BaseRepresentation
bin10100100100001100…
…00101100111101101
31001111110121010011120
422102012011213231
5140102444112023
65023331011153
7540414662034
oct122206054755
931443533146
1011041004013
1147563a4806
122181739ab9
13106c583190
1476a50571b
1544948d8e3
hex2921859ed

11041004013 has 16 divisors (see below), whose sum is σ = 16191065856. Its totient is φ = 6649899840.

The previous prime is 11041004011. The next prime is 11041004027. The reversal of 11041004013 is 31040014011.

It is not a de Polignac number, because 11041004013 - 21 = 11041004011 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11041003983 and 11041004001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11041004011) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3009898 + ... + 3013563.

It is an arithmetic number, because the mean of its divisors is an integer number (1011941616).

Almost surely, 211041004013 is an apocalyptic number.

11041004013 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11041004013 is a deficient number, since it is larger than the sum of its proper divisors (5150061843).

11041004013 is a wasteful number, since it uses less digits than its factorization.

11041004013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6023524.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 11041004013 its reverse (31040014011), we get a palindrome (42081018024).

The spelling of 11041004013 in words is "eleven billion, forty-one million, four thousand, thirteen".

Divisors: 1 3 13 39 47 141 611 1833 6023461 18070383 78304993 234914979 283102667 849308001 3680334671 11041004013