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1104114100003 is a prime number
BaseRepresentation
bin10000000100010010010…
…101000010011100100011
310220112220121110200221221
4100010102111002130203
5121042211202200003
62203120100555511
7142524656000125
oct20042225023443
93815817420857
101104114100003
11396285697242
12159b996b2b97
138016b239285
143b621a3d215
151dac1c637bd
hex10112542723

1104114100003 has 2 divisors, whose sum is σ = 1104114100004. Its totient is φ = 1104114100002.

The previous prime is 1104114099989. The next prime is 1104114100013. The reversal of 1104114100003 is 3000014114011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1104114100003 - 229 = 1103577229091 is a prime.

It is a super-3 number, since 3×11041141000033 (a number of 37 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1104114100003.

It is not a weakly prime, because it can be changed into another prime (1104114100013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552057050001 + 552057050002.

It is an arithmetic number, because the mean of its divisors is an integer number (552057050002).

Almost surely, 21104114100003 is an apocalyptic number.

1104114100003 is a deficient number, since it is larger than the sum of its proper divisors (1).

1104114100003 is an equidigital number, since it uses as much as digits as its factorization.

1104114100003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 1104114100003 its reverse (3000014114011), we get a palindrome (4104128214014).

The spelling of 1104114100003 in words is "one trillion, one hundred four billion, one hundred fourteen million, one hundred thousand, three".