Base | Representation |
---|---|
bin | 110011011010100100… |
… | …1000001010011001001 |
3 | 101112222212221212220211 |
4 | 1212311021001103021 |
5 | 3302111241114423 |
6 | 122420110321121 |
7 | 10656066624364 |
oct | 1466511012311 |
9 | 345885855824 |
10 | 110413223113 |
11 | 4290a427816 |
12 | 194951b91a1 |
13 | a547cbb11b |
14 | 54b602b0db |
15 | 2d1351e10d |
hex | 19b52414c9 |
110413223113 has 2 divisors, whose sum is σ = 110413223114. Its totient is φ = 110413223112.
The previous prime is 110413223093. The next prime is 110413223159. The reversal of 110413223113 is 311322314011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 63913907344 + 46499315769 = 252812^2 + 215637^2 .
It is a cyclic number.
It is not a de Polignac number, because 110413223113 - 213 = 110413214921 is a prime.
It is a super-2 number, since 2×1104132231132 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (110453223113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55206611556 + 55206611557.
It is an arithmetic number, because the mean of its divisors is an integer number (55206611557).
Almost surely, 2110413223113 is an apocalyptic number.
It is an amenable number.
110413223113 is a deficient number, since it is larger than the sum of its proper divisors (1).
110413223113 is an equidigital number, since it uses as much as digits as its factorization.
110413223113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 110413223113 its reverse (311322314011), we get a palindrome (421735537124).
The spelling of 110413223113 in words is "one hundred ten billion, four hundred thirteen million, two hundred twenty-three thousand, one hundred thirteen".
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