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110413302312142 = 255206651156071
BaseRepresentation
bin11001000110101110011001…
…101010011010110011001110
3112110221102000212202121212101
4121012232121222122303032
5103433002420342442032
61030455100522425314
732154045363304654
oct3106563152326316
9473842025677771
10110413302312142
11321aa022760595
1210472a0766223a
13497bc1180b7cb
141d3a064a84dd4
15cb7183d76de7
hex646b99a9acce

110413302312142 has 4 divisors (see below), whose sum is σ = 165619953468216. Its totient is φ = 55206651156070.

The previous prime is 110413302312133. The next prime is 110413302312193. The reversal of 110413302312142 is 241213203314011.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 110413302312142.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27603325578034 + ... + 27603325578037.

It is an arithmetic number, because the mean of its divisors is an integer number (41404988367054).

Almost surely, 2110413302312142 is an apocalyptic number.

110413302312142 is a deficient number, since it is larger than the sum of its proper divisors (55206651156074).

110413302312142 is an equidigital number, since it uses as much as digits as its factorization.

110413302312142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55206651156073.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 110413302312142 its reverse (241213203314011), we get a palindrome (351626505626153).

The spelling of 110413302312142 in words is "one hundred ten trillion, four hundred thirteen billion, three hundred two million, three hundred twelve thousand, one hundred forty-two".

Divisors: 1 2 55206651156071 110413302312142