110413513412401 has 2 divisors, whose sum is σ = 110413513412402. Its totient is φ = 110413513412400.

The previous prime is 110413513412333. The next prime is 110413513412443. The reversal of 110413513412401 is 104214315314011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 85742414478400 + 24671098934001 = 9259720^2 + 4967001^2 .

It is a cyclic number.

It is not a de Polignac number, because 110413513412401 - 2²¹ = 110413511315249 is a prime.

It is a super-2 number, since 2×110413513412401² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (110413513419401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55206756706200 + 55206756706201.

It is an arithmetic number, because the mean of its divisors is an integer number (55206756706201).

Almost surely, 2^{110413513412401} is an apocalyptic number.

It is an amenable number.

110413513412401 is a deficient number, since it is larger than the sum of its proper divisors (1).

110413513412401 is an equidigital number, since it uses as much as digits as its factorization.

110413513412401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 31.

Adding to 110413513412401 its reverse (104214315314011), we get a palindrome (214627828726412).

The spelling of 110413513412401 in words is "one hundred ten trillion, four hundred thirteen billion, five hundred thirteen million, four hundred twelve thousand, four hundred one".