Base | Representation |
---|---|
bin | 110011011010110011… |
… | …1011101000111111011 |
3 | 101120000102222020002001 |
4 | 1212311213131013323 |
5 | 3302120311421103 |
6 | 122420553321431 |
7 | 10656224503612 |
oct | 1466547350773 |
9 | 346012866061 |
10 | 110421201403 |
11 | 42913986a47 |
12 | 19497a06277 |
13 | a5498526c6 |
14 | 54b7106879 |
15 | 2d1409801d |
hex | 19b59dd1fb |
110421201403 has 2 divisors, whose sum is σ = 110421201404. Its totient is φ = 110421201402.
The previous prime is 110421201367. The next prime is 110421201463. The reversal of 110421201403 is 304102124011.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110421201403 is a prime.
It is not a weakly prime, because it can be changed into another prime (110421201463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55210600701 + 55210600702.
It is an arithmetic number, because the mean of its divisors is an integer number (55210600702).
Almost surely, 2110421201403 is an apocalyptic number.
110421201403 is a deficient number, since it is larger than the sum of its proper divisors (1).
110421201403 is an equidigital number, since it uses as much as digits as its factorization.
110421201403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 110421201403 its reverse (304102124011), we get a palindrome (414523325414).
The spelling of 110421201403 in words is "one hundred ten billion, four hundred twenty-one million, two hundred one thousand, four hundred three".
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