Base | Representation |
---|---|
bin | 110011011010110111… |
… | …0010111011111100011 |
3 | 101120000120101021121002 |
4 | 1212311232113133203 |
5 | 3302121242411342 |
6 | 122421100222215 |
7 | 10656246061343 |
oct | 1466556273743 |
9 | 346016337532 |
10 | 110423013347 |
11 | 42914a04319 |
12 | 1949853a96b |
13 | a54a03836a |
14 | 54b7458d23 |
15 | 2d14304d32 |
hex | 19b5b977e3 |
110423013347 has 2 divisors, whose sum is σ = 110423013348. Its totient is φ = 110423013346.
The previous prime is 110423013329. The next prime is 110423013367. The reversal of 110423013347 is 743310324011.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110423013347 is a prime.
It is not a weakly prime, because it can be changed into another prime (110423013367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55211506673 + 55211506674.
It is an arithmetic number, because the mean of its divisors is an integer number (55211506674).
Almost surely, 2110423013347 is an apocalyptic number.
110423013347 is a deficient number, since it is larger than the sum of its proper divisors (1).
110423013347 is an equidigital number, since it uses as much as digits as its factorization.
110423013347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 29.
Adding to 110423013347 its reverse (743310324011), we get a palindrome (853733337358).
The spelling of 110423013347 in words is "one hundred ten billion, four hundred twenty-three million, thirteen thousand, three hundred forty-seven".
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