Base | Representation |
---|---|
bin | 1010000010101111110100… |
… | …1010111011001001100011 |
3 | 1110002122010210212122201022 |
4 | 2200223331022323021203 |
5 | 2421404124220400313 |
6 | 35252434015400055 |
7 | 2216531551444466 |
oct | 240537512731143 |
9 | 43078123778638 |
10 | 11042313450083 |
11 | 3578023085273 |
12 | 12a40a852302b |
13 | 62139387a796 |
14 | 2a26450b32dd |
15 | 14238131cc08 |
hex | a0afd2bb263 |
11042313450083 has 2 divisors, whose sum is σ = 11042313450084. Its totient is φ = 11042313450082.
The previous prime is 11042313450011. The next prime is 11042313450097. The reversal of 11042313450083 is 38005431324011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11042313450083 - 212 = 11042313445987 is a prime.
It is not a weakly prime, because it can be changed into another prime (11042313450683) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5521156725041 + 5521156725042.
It is an arithmetic number, because the mean of its divisors is an integer number (5521156725042).
Almost surely, 211042313450083 is an apocalyptic number.
11042313450083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11042313450083 is an equidigital number, since it uses as much as digits as its factorization.
11042313450083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 34560, while the sum is 35.
Adding to 11042313450083 its reverse (38005431324011), we get a palindrome (49047744774094).
The spelling of 11042313450083 in words is "eleven trillion, forty-two billion, three hundred thirteen million, four hundred fifty thousand, eighty-three".
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