Base | Representation |
---|---|
bin | 110011011011001000… |
… | …0101001100010000011 |
3 | 101120001012021212010221 |
4 | 1212312100221202003 |
5 | 3302131043001011 |
6 | 122422021003511 |
7 | 10656415341025 |
oct | 1466620514203 |
9 | 346035255127 |
10 | 110432000131 |
11 | 42919a92212 |
12 | 1949b553597 |
13 | a54bb6399b |
14 | 54b8718015 |
15 | 2d14ecc971 |
hex | 19b6429883 |
110432000131 has 2 divisors, whose sum is σ = 110432000132. Its totient is φ = 110432000130.
The previous prime is 110432000113. The next prime is 110432000171. The reversal of 110432000131 is 131000234011.
Together with previous prime (110432000113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is an emirp because it is prime and its reverse (131000234011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110432000131 - 29 = 110431999619 is a prime.
It is a super-2 number, since 2×1104320001312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (110432000171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55216000065 + 55216000066.
It is an arithmetic number, because the mean of its divisors is an integer number (55216000066).
Almost surely, 2110432000131 is an apocalyptic number.
110432000131 is a deficient number, since it is larger than the sum of its proper divisors (1).
110432000131 is an equidigital number, since it uses as much as digits as its factorization.
110432000131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 110432000131 its reverse (131000234011), we get a palindrome (241432234142).
The spelling of 110432000131 in words is "one hundred ten billion, four hundred thirty-two million, one hundred thirty-one", and thus it is an aban number.
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