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1104331242331 is a prime number
BaseRepresentation
bin10000000100011111010…
…001010111101101011011
310220120110202001200020101
4100010133101113231123
5121043132244223311
62203153415040231
7142533233452132
oct20043721275533
93816422050211
101104331242331
11396387218509
1215a03a370077
13801a4216065
143b642804919
151dad5d56ec1
hex1011f457b5b

1104331242331 has 2 divisors, whose sum is σ = 1104331242332. Its totient is φ = 1104331242330.

The previous prime is 1104331242293. The next prime is 1104331242349. The reversal of 1104331242331 is 1332421334011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1104331242331 - 235 = 1069971503963 is a prime.

It is a super-2 number, since 2×11043312423312 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1104331242331.

It is not a weakly prime, because it can be changed into another prime (1104331242361) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552165621165 + 552165621166.

It is an arithmetic number, because the mean of its divisors is an integer number (552165621166).

Almost surely, 21104331242331 is an apocalyptic number.

1104331242331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1104331242331 is an equidigital number, since it uses as much as digits as its factorization.

1104331242331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1104331242331 its reverse (1332421334011), we get a palindrome (2436752576342).

The spelling of 1104331242331 in words is "one trillion, one hundred four billion, three hundred thirty-one million, two hundred forty-two thousand, three hundred thirty-one".