Base | Representation |
---|---|
bin | 1010000010110011100100… |
… | …1100111010011010111111 |
3 | 1110002201202000000101122020 |
4 | 2200230321030322122333 |
5 | 2421413210033314401 |
6 | 35253121554251223 |
7 | 2216565531223350 |
oct | 240547114723277 |
9 | 43081660011566 |
10 | 11043320604351 |
11 | 357849a645172 |
12 | 12a4329886b13 |
13 | 6214c4421159 |
14 | 2a26dcb63d27 |
15 | 1423de963d36 |
hex | a0b3933a6bf |
11043320604351 has 32 divisors (see below), whose sum is σ = 17755672281600. Its totient is φ = 5964138552960.
The previous prime is 11043320604247. The next prime is 11043320604361. The reversal of 11043320604351 is 15340602334011.
It is not a de Polignac number, because 11043320604351 - 215 = 11043320571583 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11043320604361) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 32703156 + ... + 33039113.
It is an arithmetic number, because the mean of its divisors is an integer number (554864758800).
Almost surely, 211043320604351 is an apocalyptic number.
11043320604351 is a deficient number, since it is larger than the sum of its proper divisors (6712351677249).
11043320604351 is a wasteful number, since it uses less digits than its factorization.
11043320604351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65742719.
The product of its (nonzero) digits is 25920, while the sum is 33.
Adding to 11043320604351 its reverse (15340602334011), we get a palindrome (26383922938362).
The spelling of 11043320604351 in words is "eleven trillion, forty-three billion, three hundred twenty million, six hundred four thousand, three hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •