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110440020131 = 715777145733
BaseRepresentation
bin110011011011010111…
…1001111100010100011
3101120001202101022111222
41212312233033202203
53302140121121011
6122422504525255
710656543452660
oct1466657174243
9346052338458
10110440020131
114292356a811
12194a218082b
13a55071124c
1454b9804a67
152d15a63ddb
hex19b6bcf8a3

110440020131 has 4 divisors (see below), whose sum is σ = 126217165872. Its totient is φ = 94662874392.

The previous prime is 110440020109. The next prime is 110440020139. The reversal of 110440020131 is 131020044011.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110440020131 is a prime.

It is a super-2 number, since 2×1104400201312 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (110440020139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7888572860 + ... + 7888572873.

It is an arithmetic number, because the mean of its divisors is an integer number (31554291468).

Almost surely, 2110440020131 is an apocalyptic number.

110440020131 is a deficient number, since it is larger than the sum of its proper divisors (15777145741).

110440020131 is an equidigital number, since it uses as much as digits as its factorization.

110440020131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15777145740.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 110440020131 its reverse (131020044011), we get a palindrome (241460064142).

The spelling of 110440020131 in words is "one hundred ten billion, four hundred forty million, twenty thousand, one hundred thirty-one".

Divisors: 1 7 15777145733 110440020131