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1104406149139 is a prime number
BaseRepresentation
bin10000000100100011101…
…111000111100000010011
310220120122222000100001121
4100010203233013200103
5121043310433233024
62203205052343111
7142535133243256
oct20044357074023
93816588010047
101104406149139
11396415530067
1215a05b474a97
13801b68b2107
143b64c74309d
151dadc7018e4
hex10123bc7813

1104406149139 has 2 divisors, whose sum is σ = 1104406149140. Its totient is φ = 1104406149138.

The previous prime is 1104406149109. The next prime is 1104406149173. The reversal of 1104406149139 is 9319416044011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1104406149139 - 25 = 1104406149107 is a prime.

It is a super-2 number, since 2×11044061491392 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1104406149095 and 1104406149104.

It is not a weakly prime, because it can be changed into another prime (1104406149109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552203074569 + 552203074570.

It is an arithmetic number, because the mean of its divisors is an integer number (552203074570).

Almost surely, 21104406149139 is an apocalyptic number.

1104406149139 is a deficient number, since it is larger than the sum of its proper divisors (1).

1104406149139 is an equidigital number, since it uses as much as digits as its factorization.

1104406149139 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 93312, while the sum is 43.

The spelling of 1104406149139 in words is "one trillion, one hundred four billion, four hundred six million, one hundred forty-nine thousand, one hundred thirty-nine".