Base | Representation |
---|---|
bin | 10100100100100100… |
… | …10101010101110011 |
3 | 1001111200122012121211 |
4 | 22102102111111303 |
5 | 140104304323011 |
6 | 5023523500551 |
7 | 540454162006 |
oct | 122222252563 |
9 | 31450565554 |
10 | 11044214131 |
11 | 47581975a5 |
12 | 2182827757 |
13 | 1070138362 |
14 | 76aadd53d |
15 | 4498c4b21 |
hex | 292495573 |
11044214131 has 2 divisors, whose sum is σ = 11044214132. Its totient is φ = 11044214130.
The previous prime is 11044214123. The next prime is 11044214149. The reversal of 11044214131 is 13141244011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11044214131 - 23 = 11044214123 is a prime.
It is a super-2 number, since 2×110442141312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11044214161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5522107065 + 5522107066.
It is an arithmetic number, because the mean of its divisors is an integer number (5522107066).
Almost surely, 211044214131 is an apocalyptic number.
11044214131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11044214131 is an equidigital number, since it uses as much as digits as its factorization.
11044214131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 11044214131 its reverse (13141244011), we get a palindrome (24185458142).
The spelling of 11044214131 in words is "eleven billion, forty-four million, two hundred fourteen thousand, one hundred thirty-one".
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