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11051124136343 = 19357259710551
BaseRepresentation
bin1010000011010000101001…
…0101000001100110010111
31110010110212211201220002122
42200310022111001212113
52422030200234330333
635300452155130155
72220263105156444
oct240641225014627
943113784656078
1011051124136343
113580834522265
1212a594714395b
136221690457c5
142a2c3d2c89cb
151426e9aa1798
hexa0d0a541997

11051124136343 has 4 divisors (see below), whose sum is σ = 11108383847088. Its totient is φ = 10993864425600.

The previous prime is 11051124136289. The next prime is 11051124136457. The reversal of 11051124136343 is 34363142115011.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11051124136343 is a prime.

It is a super-3 number, since 3×110511241363433 (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11051124135343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28629855083 + ... + 28629855468.

It is an arithmetic number, because the mean of its divisors is an integer number (2777095961772).

Almost surely, 211051124136343 is an apocalyptic number.

11051124136343 is a deficient number, since it is larger than the sum of its proper divisors (57259710745).

11051124136343 is an equidigital number, since it uses as much as digits as its factorization.

11051124136343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 57259710744.

The product of its (nonzero) digits is 25920, while the sum is 35.

The spelling of 11051124136343 in words is "eleven trillion, fifty-one billion, one hundred twenty-four million, one hundred thirty-six thousand, three hundred forty-three".

Divisors: 1 193 57259710551 11051124136343