Base | Representation |
---|---|
bin | 1010000011010100000010… |
… | …1000000101111001001111 |
3 | 1110010120020022212212020220 |
4 | 2200311000220011321033 |
5 | 2422034031441314320 |
6 | 35301122420242423 |
7 | 2220324506236011 |
oct | 240650050057117 |
9 | 43116208785226 |
10 | 11052035104335 |
11 | 3581161765a75 |
12 | 12a5b60240413 |
13 | 6222829ac514 |
14 | 2a2cc829c1b1 |
15 | 14274ea47e40 |
hex | a0d40a05e4f |
11052035104335 has 32 divisors (see below), whose sum is σ = 17725022692608. Its totient is φ = 5880497978880.
The previous prime is 11052035104273. The next prime is 11052035104381. The reversal of 11052035104335 is 53340153025011.
It is not a de Polignac number, because 11052035104335 - 28 = 11052035104079 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11052035104296 and 11052035104305.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 180290040 + ... + 180351330.
It is an arithmetic number, because the mean of its divisors is an integer number (553906959144).
Almost surely, 211052035104335 is an apocalyptic number.
11052035104335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11052035104335 is a deficient number, since it is larger than the sum of its proper divisors (6672987588273).
11052035104335 is a wasteful number, since it uses less digits than its factorization.
11052035104335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 89495.
The product of its (nonzero) digits is 27000, while the sum is 33.
Adding to 11052035104335 its reverse (53340153025011), we get a palindrome (64392188129346).
The spelling of 11052035104335 in words is "eleven trillion, fifty-two billion, thirty-five million, one hundred four thousand, three hundred thirty-five".
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