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11052125051147 is a prime number
BaseRepresentation
bin1010000011010100010111…
…1111001101100100001011
31110010120110121010122002022
42200311011333031210023
52422034223003114042
635301135352155055
72220326650620425
oct240650577154413
943116417118068
1011052125051147
1135811a8510384
1212a5b86398a8b
1362229851319b
142a2cd61d3815
151427578b3cd2
hexa0d45fcd90b

11052125051147 has 2 divisors, whose sum is σ = 11052125051148. Its totient is φ = 11052125051146.

The previous prime is 11052125051041. The next prime is 11052125051273. The reversal of 11052125051147 is 74115052125011.

11052125051147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11052125051147 - 218 = 11052124789003 is a prime.

It is not a weakly prime, because it can be changed into another prime (11052125051647) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5526062525573 + 5526062525574.

It is an arithmetic number, because the mean of its divisors is an integer number (5526062525574).

Almost surely, 211052125051147 is an apocalyptic number.

11052125051147 is a deficient number, since it is larger than the sum of its proper divisors (1).

11052125051147 is an equidigital number, since it uses as much as digits as its factorization.

11052125051147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14000, while the sum is 35.

Adding to 11052125051147 its reverse (74115052125011), we get a palindrome (85167177176158).

The spelling of 11052125051147 in words is "eleven trillion, fifty-two billion, one hundred twenty-five million, fifty-one thousand, one hundred forty-seven".