Base | Representation |
---|---|
bin | 1010000011010100010111… |
… | …1111001101100100001011 |
3 | 1110010120110121010122002022 |
4 | 2200311011333031210023 |
5 | 2422034223003114042 |
6 | 35301135352155055 |
7 | 2220326650620425 |
oct | 240650577154413 |
9 | 43116417118068 |
10 | 11052125051147 |
11 | 35811a8510384 |
12 | 12a5b86398a8b |
13 | 62229851319b |
14 | 2a2cd61d3815 |
15 | 1427578b3cd2 |
hex | a0d45fcd90b |
11052125051147 has 2 divisors, whose sum is σ = 11052125051148. Its totient is φ = 11052125051146.
The previous prime is 11052125051041. The next prime is 11052125051273. The reversal of 11052125051147 is 74115052125011.
11052125051147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11052125051147 - 218 = 11052124789003 is a prime.
It is not a weakly prime, because it can be changed into another prime (11052125051647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5526062525573 + 5526062525574.
It is an arithmetic number, because the mean of its divisors is an integer number (5526062525574).
Almost surely, 211052125051147 is an apocalyptic number.
11052125051147 is a deficient number, since it is larger than the sum of its proper divisors (1).
11052125051147 is an equidigital number, since it uses as much as digits as its factorization.
11052125051147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14000, while the sum is 35.
Adding to 11052125051147 its reverse (74115052125011), we get a palindrome (85167177176158).
The spelling of 11052125051147 in words is "eleven trillion, fifty-two billion, one hundred twenty-five million, fifty-one thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.192 sec. • engine limits •