Base | Representation |
---|---|
bin | 10100100101101001… |
… | …10100011110011011 |
3 | 1001112022122111202100 |
4 | 22102310310132123 |
5 | 140114113121210 |
6 | 5024445334443 |
7 | 540624053640 |
oct | 122264643633 |
9 | 31468574670 |
10 | 11053254555 |
11 | 4762301822 |
12 | 2185867423 |
13 | 1071c82215 |
14 | 76bdb3dc7 |
15 | 44a5ad5c0 |
hex | 292d3479b |
11053254555 has 48 divisors (see below), whose sum is σ = 22847984640. Its totient is φ = 4833221184.
The previous prime is 11053254539. The next prime is 11053254571. The reversal of 11053254555 is 55545235011.
11053254555 is a `hidden beast` number, since 1 + 1 + 0 + 53 + 2 + 54 + 555 = 666.
It is an interprime number because it is at equal distance from previous prime (11053254539) and next prime (11053254571).
It is not a de Polignac number, because 11053254555 - 24 = 11053254539 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 755575 + ... + 770064.
It is an arithmetic number, because the mean of its divisors is an integer number (475999680).
Almost surely, 211053254555 is an apocalyptic number.
11053254555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11053254555 is an abundant number, since it is smaller than the sum of its proper divisors (11794730085).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11053254555 is a wasteful number, since it uses less digits than its factorization.
11053254555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1525680 (or 1525677 counting only the distinct ones).
The product of its (nonzero) digits is 75000, while the sum is 36.
Adding to 11053254555 its reverse (55545235011), we get a palindrome (66598489566).
The spelling of 11053254555 in words is "eleven billion, fifty-three million, two hundred fifty-four thousand, five hundred fifty-five".
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