110541234013 has 4 divisors (see below), whose sum is σ = 126332838880. Its totient is φ = 94749629148.

The previous prime is 110541233987. The next prime is 110541234043. The reversal of 110541234013 is 310432145011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 310432145011 = 7789 ⋅39855199.

It is a cyclic number.

It is not a de Polignac number, because 110541234013 - 2¹⁷ = 110541102941 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110541234043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7895802423 + ... + 7895802436.

It is an arithmetic number, because the mean of its divisors is an integer number (31583209720).

Almost surely, 2^110541234013 is an apocalyptic number.

It is an amenable number.

110541234013 is a deficient number, since it is larger than the sum of its proper divisors (15791604867).

110541234013 is an equidigital number, since it uses as much as digits as its factorization.

110541234013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15791604866.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 110541234013 its reverse (310432145011), we get a palindrome (420973379024).

The spelling of 110541234013 in words is "one hundred ten billion, five hundred forty-one million, two hundred thirty-four thousand, thirteen".