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11055332433 = 347199339341
BaseRepresentation
bin10100100101111001…
…01111110001010001
31001112110120002001210
422102330233301101
5140120131114213
65025002050333
7540650526615
oct122274576121
931473502053
1011055332433
1147634a0982
1221864a99a9
13107252bc32
1476c395345
1544a86e0c3
hex292f2fc51

11055332433 has 16 divisors (see below), whose sum is σ = 15062006016. Its totient is φ = 7209605760.

The previous prime is 11055332423. The next prime is 11055332461. The reversal of 11055332433 is 33423355011.

It is not a de Polignac number, because 11055332433 - 24 = 11055332417 is a prime.

It is a super-4 number, since 4×110553324334 (a number of 41 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3.

It is a self number, because there is not a number n which added to its sum of digits gives 11055332433.

It is not an unprimeable number, because it can be changed into a prime (11055332423) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 261343 + ... + 300683.

It is an arithmetic number, because the mean of its divisors is an integer number (941375376).

Almost surely, 211055332433 is an apocalyptic number.

It is an amenable number.

11055332433 is a deficient number, since it is larger than the sum of its proper divisors (4006673583).

11055332433 is a wasteful number, since it uses less digits than its factorization.

11055332433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41384.

The product of its (nonzero) digits is 16200, while the sum is 30.

Adding to 11055332433 its reverse (33423355011), we get a palindrome (44478687444).

The spelling of 11055332433 in words is "eleven billion, fifty-five million, three hundred thirty-two thousand, four hundred thirty-three".

Divisors: 1 3 47 141 1993 5979 39341 93671 118023 281013 1849027 5547081 78406613 235219839 3685110811 11055332433