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11055446412953 is a prime number
BaseRepresentation
bin1010000011100000101111…
…1101001100111010011001
31110010220001001212021221112
42200320023331030322121
52422113023240203303
635302445120350105
72220505161003125
oct240701375147231
943126031767845
1011055446412953
113582652315698
1212a6752775335
136226a7664727
142a312d370585
1514289e2860d8
hexa0e0bf4ce99

11055446412953 has 2 divisors, whose sum is σ = 11055446412954. Its totient is φ = 11055446412952.

The previous prime is 11055446412949. The next prime is 11055446413013. The reversal of 11055446412953 is 35921464455011.

11055446412953 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7346636779024 + 3708809633929 = 2710468^2 + 1925827^2 .

It is a cyclic number.

It is not a de Polignac number, because 11055446412953 - 22 = 11055446412949 is a prime.

It is not a weakly prime, because it can be changed into another prime (11055446411953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5527723206476 + 5527723206477.

It is an arithmetic number, because the mean of its divisors is an integer number (5527723206477).

Almost surely, 211055446412953 is an apocalyptic number.

It is an amenable number.

11055446412953 is a deficient number, since it is larger than the sum of its proper divisors (1).

11055446412953 is an equidigital number, since it uses as much as digits as its factorization.

11055446412953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592000, while the sum is 50.

The spelling of 11055446412953 in words is "eleven trillion, fifty-five billion, four hundred forty-six million, four hundred twelve thousand, nine hundred fifty-three".