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11055903 = 33685301
BaseRepresentation
bin101010001011…
…001100011111
3202210200211220
4222023030133
510312242103
61032544423
7162654645
oct52131437
922720756
1011055903
116271511
123852113
1323a1371
14167b195
15e85c53
hexa8b31f

11055903 has 4 divisors (see below), whose sum is σ = 14741208. Its totient is φ = 7370600.

The previous prime is 11055887. The next prime is 11055953. The reversal of 11055903 is 30955011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11055903 - 24 = 11055887 is a prime.

It is a super-2 number, since 2×110559032 = 244465982290818, which contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11055953) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1842648 + ... + 1842653.

It is an arithmetic number, because the mean of its divisors is an integer number (3685302).

Almost surely, 211055903 is an apocalyptic number.

11055903 is a deficient number, since it is larger than the sum of its proper divisors (3685305).

11055903 is an equidigital number, since it uses as much as digits as its factorization.

11055903 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3685304.

The product of its (nonzero) digits is 675, while the sum is 24.

The square root of 11055903 is about 3325.0418042485. The cubic root of 11055903 is about 222.7741215953.

The spelling of 11055903 in words is "eleven million, fifty-five thousand, nine hundred three".

Divisors: 1 3 3685301 11055903