Base | Representation |
---|---|
bin | 10100100110001000… |
… | …01011011010000011 |
3 | 1001112121020001111201 |
4 | 22103010023122003 |
5 | 140121130440033 |
6 | 5025111522031 |
7 | 541003222543 |
oct | 122304133203 |
9 | 31477201451 |
10 | 11057280643 |
11 | 4764601672 |
12 | 2187089317 |
13 | 1072a61916 |
14 | 76c741323 |
15 | 44ab0647d |
hex | 29310b683 |
11057280643 has 2 divisors, whose sum is σ = 11057280644. Its totient is φ = 11057280642.
The previous prime is 11057280599. The next prime is 11057280671. The reversal of 11057280643 is 34608275011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11057280643 is a prime.
It is a super-3 number, since 3×110572806433 (a number of 31 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (11057280673) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5528640321 + 5528640322.
It is an arithmetic number, because the mean of its divisors is an integer number (5528640322).
Almost surely, 211057280643 is an apocalyptic number.
11057280643 is a deficient number, since it is larger than the sum of its proper divisors (1).
11057280643 is an equidigital number, since it uses as much as digits as its factorization.
11057280643 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40320, while the sum is 37.
The spelling of 11057280643 in words is "eleven billion, fifty-seven million, two hundred eighty thousand, six hundred forty-three".
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