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11060502795113 is a prime number
BaseRepresentation
bin1010000011110011100101…
…0101110001001101101001
31110011101002110100010021212
42200330321111301031221
52422203402203420423
635305042544242505
72221044366356102
oct240747125611551
943141073303255
1011060502795113
113584807532422
1212a7724010435
136230020a4635
142a348cb0b3a9
15142a98128578
hexa0f39571369

11060502795113 has 2 divisors, whose sum is σ = 11060502795114. Its totient is φ = 11060502795112.

The previous prime is 11060502795077. The next prime is 11060502795151. The reversal of 11060502795113 is 31159720506011.

11060502795113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8614647645184 + 2445855149929 = 2935072^2 + 1563923^2 .

It is an emirp because it is prime and its reverse (31159720506011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11060502795113 - 26 = 11060502795049 is a prime.

It is not a weakly prime, because it can be changed into another prime (11060502795163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5530251397556 + 5530251397557.

It is an arithmetic number, because the mean of its divisors is an integer number (5530251397557).

Almost surely, 211060502795113 is an apocalyptic number.

It is an amenable number.

11060502795113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11060502795113 is an equidigital number, since it uses as much as digits as its factorization.

11060502795113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56700, while the sum is 41.

The spelling of 11060502795113 in words is "eleven trillion, sixty billion, five hundred two million, seven hundred ninety-five thousand, one hundred thirteen".