Base | Representation |
---|---|
bin | 10100100111000111… |
… | …01000001110110001 |
3 | 1001120011201220212112 |
4 | 22103203220032301 |
5 | 140130233301134 |
6 | 5030004335105 |
7 | 541133261216 |
oct | 122343501661 |
9 | 31504656775 |
10 | 11065525169 |
11 | 4769222926 |
12 | 21899a4495 |
13 | 107468a43a |
14 | 76d889b0d |
15 | 44b6d41ce |
hex | 2938e83b1 |
11065525169 has 2 divisors, whose sum is σ = 11065525170. Its totient is φ = 11065525168.
The previous prime is 11065525151. The next prime is 11065525249. The reversal of 11065525169 is 96152556011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6195578944 + 4869946225 = 78712^2 + 69785^2 .
It is an emirp because it is prime and its reverse (96152556011) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11065525169 is a prime.
It is a super-2 number, since 2×110655251692 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11065525069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5532762584 + 5532762585.
It is an arithmetic number, because the mean of its divisors is an integer number (5532762585).
Almost surely, 211065525169 is an apocalyptic number.
It is an amenable number.
11065525169 is a deficient number, since it is larger than the sum of its proper divisors (1).
11065525169 is an equidigital number, since it uses as much as digits as its factorization.
11065525169 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81000, while the sum is 41.
The spelling of 11065525169 in words is "eleven billion, sixty-five million, five hundred twenty-five thousand, one hundred sixty-nine".
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