Search a number
-
+
110713526889491 is a prime number
BaseRepresentation
bin11001001011000110000000…
…011100010010110000010011
3112112000002222001021100211002
4121023012000130102300103
5104002412300340430431
61031245031521212215
732214534256146641
oct3113060034226023
9475002861240732
10110713526889491
11323053856a70a9
121050103419106b
1349a131901b406
141d4a7c5966191
15cbeda60e73cb
hex64b180712c13

110713526889491 has 2 divisors, whose sum is σ = 110713526889492. Its totient is φ = 110713526889490.

The previous prime is 110713526889457. The next prime is 110713526889523. The reversal of 110713526889491 is 194988625317011.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110713526889491 is a prime.

It is not a weakly prime, because it can be changed into another prime (110713529889491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55356763444745 + 55356763444746.

It is an arithmetic number, because the mean of its divisors is an integer number (55356763444746).

It is a 1-persistent number, because it is pandigital, but 2⋅110713526889491 = 221427053778982 is not.

Almost surely, 2110713526889491 is an apocalyptic number.

110713526889491 is a deficient number, since it is larger than the sum of its proper divisors (1).

110713526889491 is an equidigital number, since it uses as much as digits as its factorization.

110713526889491 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26127360, while the sum is 65.

The spelling of 110713526889491 in words is "one hundred ten trillion, seven hundred thirteen billion, five hundred twenty-six million, eight hundred eighty-nine thousand, four hundred ninety-one".