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11075100833 is a prime number
BaseRepresentation
bin10100101000010000…
…01010000010100001
31001120211202102012202
422110020022002201
5140140211211313
65030545502545
7541310542466
oct122410120241
931524672182
1011075100833
1147736731a5
122191041a55
131076660b04
14770c5d66d
1544c476558
hex29420a0a1

11075100833 has 2 divisors, whose sum is σ = 11075100834. Its totient is φ = 11075100832.

The previous prime is 11075100749. The next prime is 11075100923. The reversal of 11075100833 is 33800157011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6871912609 + 4203188224 = 82897^2 + 64832^2 .

It is a cyclic number.

It is not a de Polignac number, because 11075100833 - 28 = 11075100577 is a prime.

It is a super-2 number, since 2×110751008332 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11075100796 and 11075100805.

It is not a weakly prime, because it can be changed into another prime (11075100233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5537550416 + 5537550417.

It is an arithmetic number, because the mean of its divisors is an integer number (5537550417).

Almost surely, 211075100833 is an apocalyptic number.

It is an amenable number.

11075100833 is a deficient number, since it is larger than the sum of its proper divisors (1).

11075100833 is an equidigital number, since it uses as much as digits as its factorization.

11075100833 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2520, while the sum is 29.

Adding to 11075100833 its reverse (33800157011), we get a palindrome (44875257844).

The spelling of 11075100833 in words is "eleven billion, seventy-five million, one hundred thousand, eight hundred thirty-three".