Base | Representation |
---|---|
bin | 10000000111111100011… |
… | …010101011111010011001 |
3 | 10220221001022110201010101 |
4 | 100013330122223322121 |
5 | 121123232102332423 |
6 | 2205005513415401 |
7 | 143024204626414 |
oct | 20077432537231 |
9 | 3827038421111 |
10 | 1108041449113 |
11 | 397a10569805 |
12 | 15a8b4a0a561 |
13 | 80645aa16a1 |
14 | 3b8b5480b7b |
15 | 1dc519377ad |
hex | 101fc6abe99 |
1108041449113 has 2 divisors, whose sum is σ = 1108041449114. Its totient is φ = 1108041449112.
The previous prime is 1108041449023. The next prime is 1108041449189. The reversal of 1108041449113 is 3119441408011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 809256770569 + 298784678544 = 899587^2 + 546612^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1108041449113 is a prime.
It is not a weakly prime, because it can be changed into another prime (1108041249113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 554020724556 + 554020724557.
It is an arithmetic number, because the mean of its divisors is an integer number (554020724557).
Almost surely, 21108041449113 is an apocalyptic number.
It is an amenable number.
1108041449113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1108041449113 is an equidigital number, since it uses as much as digits as its factorization.
1108041449113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 37.
The spelling of 1108041449113 in words is "one trillion, one hundred eight billion, forty-one million, four hundred forty-nine thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •