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11089433 is a prime number
BaseRepresentation
bin101010010011…
…011000011001
3202212101211202
4222103120121
510314330213
61033403545
7163154465
oct52233031
922771752
1011089433
116294723
1238695b5
1323b36c4
1416894a5
15e90b58
hexa93619

11089433 has 2 divisors, whose sum is σ = 11089434. Its totient is φ = 11089432.

The previous prime is 11089409. The next prime is 11089459. The reversal of 11089433 is 33498011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10220809 + 868624 = 3197^2 + 932^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11089433 is a prime.

It is a super-2 number, since 2×110894332 = 245951048522978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11089396 and 11089405.

It is not a weakly prime, because it can be changed into another prime (11089633) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5544716 + 5544717.

It is an arithmetic number, because the mean of its divisors is an integer number (5544717).

Almost surely, 211089433 is an apocalyptic number.

It is an amenable number.

11089433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11089433 is an equidigital number, since it uses as much as digits as its factorization.

11089433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 29.

The square root of 11089433 is about 3330.0800290684. The cubic root of 11089433 is about 222.9991017948. Note that the first 3 decimals are identical.

The spelling of 11089433 in words is "eleven million, eighty-nine thousand, four hundred thirty-three".