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11093450180353 is a prime number
BaseRepresentation
bin1010000101101110010100…
…1010000100011100000001
31110021112010121122201010021
42201123211022010130001
52423223341221232403
635332132145133441
72223322015462612
oct241334512043401
943245117581107
1011093450180353
11359778446a622
1212b1b9a02a281
13626152c8b668
142a4cd6783c09
151438758a18bd
hexa16e5284701

11093450180353 has 2 divisors, whose sum is σ = 11093450180354. Its totient is φ = 11093450180352.

The previous prime is 11093450180249. The next prime is 11093450180383. The reversal of 11093450180353 is 35308105439011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10293978146929 + 799472033424 = 3208423^2 + 894132^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11093450180353 is a prime.

It is a super-3 number, since 3×110934501803533 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (11093450180383) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5546725090176 + 5546725090177.

It is an arithmetic number, because the mean of its divisors is an integer number (5546725090177).

Almost surely, 211093450180353 is an apocalyptic number.

It is an amenable number.

11093450180353 is a deficient number, since it is larger than the sum of its proper divisors (1).

11093450180353 is an equidigital number, since it uses as much as digits as its factorization.

11093450180353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 194400, while the sum is 43.

The spelling of 11093450180353 in words is "eleven trillion, ninety-three billion, four hundred fifty million, one hundred eighty thousand, three hundred fifty-three".