Base | Representation |
---|---|
bin | 10100101010011101… |
… | …00011100000100001 |
3 | 1001122010110222220001 |
4 | 22111032203200201 |
5 | 140204422231413 |
6 | 5032445220001 |
7 | 541623443425 |
oct | 122516434041 |
9 | 31563428801 |
10 | 11093555233 |
11 | 4783028272 |
12 | 2197261601 |
13 | 107a422887 |
14 | 7734a4b85 |
15 | 44ddbe4dd |
hex | 2953a3821 |
11093555233 has 2 divisors, whose sum is σ = 11093555234. Its totient is φ = 11093555232.
The previous prime is 11093555219. The next prime is 11093555237. The reversal of 11093555233 is 33255539011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8477437329 + 2616117904 = 92073^2 + 51148^2 .
It is a cyclic number.
It is not a de Polignac number, because 11093555233 - 29 = 11093554721 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11093555192 and 11093555201.
It is not a weakly prime, because it can be changed into another prime (11093555237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5546777616 + 5546777617.
It is an arithmetic number, because the mean of its divisors is an integer number (5546777617).
Almost surely, 211093555233 is an apocalyptic number.
It is an amenable number.
11093555233 is a deficient number, since it is larger than the sum of its proper divisors (1).
11093555233 is an equidigital number, since it uses as much as digits as its factorization.
11093555233 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60750, while the sum is 37.
The spelling of 11093555233 in words is "eleven billion, ninety-three million, five hundred fifty-five thousand, two hundred thirty-three".
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