Base | Representation |
---|---|
bin | 1010000101110101100111… |
… | …1010000101111111010001 |
3 | 1110021201012010101022221021 |
4 | 2201131121322011333101 |
5 | 2423241344141123143 |
6 | 35333054355555441 |
7 | 2223421401525361 |
oct | 241353172057721 |
9 | 43251163338837 |
10 | 11095408926673 |
11 | 359859a09a735 |
12 | 12b2445bbbb81 |
13 | 6263a5a20656 |
14 | 2a50409809a1 |
15 | 14393c815ced |
hex | a1759e85fd1 |
11095408926673 has 2 divisors, whose sum is σ = 11095408926674. Its totient is φ = 11095408926672.
The previous prime is 11095408926631. The next prime is 11095408926677. The reversal of 11095408926673 is 37662980459011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8500822490689 + 2594586435984 = 2915617^2 + 1610772^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11095408926673 is a prime.
It is not a weakly prime, because it can be changed into another prime (11095408926677) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5547704463336 + 5547704463337.
It is an arithmetic number, because the mean of its divisors is an integer number (5547704463337).
It is a 2-persistent number, because it is pandigital, and so is 2⋅11095408926673 = 22190817853346, but 3⋅11095408926673 = 33286226780019 is not.
Almost surely, 211095408926673 is an apocalyptic number.
It is an amenable number.
11095408926673 is a deficient number, since it is larger than the sum of its proper divisors (1).
11095408926673 is an equidigital number, since it uses as much as digits as its factorization.
11095408926673 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19595520, while the sum is 61.
The spelling of 11095408926673 in words is "eleven trillion, ninety-five billion, four hundred eight million, nine hundred twenty-six thousand, six hundred seventy-three".
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