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11097120113 is a prime number
BaseRepresentation
bin10100101010111000…
…01001110101110001
31001122101012002222122
422111130021311301
5140211330320423
65033053444025
7541665651602
oct122534116561
931571162878
1011097120113
114785042652
1221984a0615
13107b0a0381
14773b51da9
1544e3758c8
hex295709d71

11097120113 has 2 divisors, whose sum is σ = 11097120114. Its totient is φ = 11097120112.

The previous prime is 11097120091. The next prime is 11097120161. The reversal of 11097120113 is 31102179011.

11097120113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11095883569 + 1236544 = 105337^2 + 1112^2 .

It is an emirp because it is prime and its reverse (31102179011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11097120113 - 26 = 11097120049 is a prime.

It is not a weakly prime, because it can be changed into another prime (11097620113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5548560056 + 5548560057.

It is an arithmetic number, because the mean of its divisors is an integer number (5548560057).

Almost surely, 211097120113 is an apocalyptic number.

It is an amenable number.

11097120113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11097120113 is an equidigital number, since it uses as much as digits as its factorization.

11097120113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 378, while the sum is 26.

Adding to 11097120113 its reverse (31102179011), we get a palindrome (42199299124).

The spelling of 11097120113 in words is "eleven billion, ninety-seven million, one hundred twenty thousand, one hundred thirteen".