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11098954517353 is a prime number
BaseRepresentation
bin1010000110000010110100…
…1111011100101101101001
31110022001100020000222222121
42201200231033130231221
52423321124324023403
635334442254151241
72223605303536423
oct241405517345551
943261306028877
1011098954517353
11359a04952646a
1212b30754b2521
1362681c4603c1
142a5299809813
15143a98c2b3bd
hexa182d3dcb69

11098954517353 has 2 divisors, whose sum is σ = 11098954517354. Its totient is φ = 11098954517352.

The previous prime is 11098954517293. The next prime is 11098954517359. The reversal of 11098954517353 is 35371545989011.

11098954517353 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8187197923584 + 2911756593769 = 2861328^2 + 1706387^2 .

It is a cyclic number.

It is not a de Polignac number, because 11098954517353 - 29 = 11098954516841 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11098954517291 and 11098954517300.

It is not a weakly prime, because it can be changed into another prime (11098954517359) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5549477258676 + 5549477258677.

It is an arithmetic number, because the mean of its divisors is an integer number (5549477258677).

Almost surely, 211098954517353 is an apocalyptic number.

It is an amenable number.

11098954517353 is a deficient number, since it is larger than the sum of its proper divisors (1).

11098954517353 is an equidigital number, since it uses as much as digits as its factorization.

11098954517353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20412000, while the sum is 61.

The spelling of 11098954517353 in words is "eleven trillion, ninety-eight billion, nine hundred fifty-four million, five hundred seventeen thousand, three hundred fifty-three".