111000012013 has 4 divisors (see below), whose sum is σ = 121090922208. Its totient is φ = 100909101820.

The previous prime is 111000011987. The next prime is 111000012059. The reversal of 111000012013 is 310210000111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 310210000111 = 11 ⋅28200909101.

It is a cyclic number.

It is not a de Polignac number, because 111000012013 - 2⁵ = 111000011981 is a prime.

It is a super-2 number, since 2×111000012013² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111000012073) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5045455081 + ... + 5045455102.

It is an arithmetic number, because the mean of its divisors is an integer number (30272730552).

Almost surely, 2^111000012013 is an apocalyptic number.

It is an amenable number.

111000012013 is a deficient number, since it is larger than the sum of its proper divisors (10090910195).

111000012013 is a wasteful number, since it uses less digits than its factorization.

111000012013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10090910194.

The product of its (nonzero) digits is 6, while the sum is 10.

Adding to 111000012013 its reverse (310210000111), we get a palindrome (421210012124).

The spelling of 111000012013 in words is "one hundred eleven billion, twelve thousand, thirteen".