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11100031130014 = 25550015565007
BaseRepresentation
bin1010000110000110110101…
…1010011001100110011110
31110022011010020212120220121
42201201231122121212132
52423330330432130024
635335141153505154
72223644055565021
oct241415532314636
943264106776817
1011100031130014
11359a5512174a2
1212b3315b721ba
13626961512c08
142a535c7bb1b8
15143b0d4e28e4
hexa186d69999e

11100031130014 has 4 divisors (see below), whose sum is σ = 16650046695024. Its totient is φ = 5550015565006.

The previous prime is 11100031129981. The next prime is 11100031130021. The reversal of 11100031130014 is 41003113000111.

11100031130014 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 11100031130014.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2775007782502 + ... + 2775007782505.

It is an arithmetic number, because the mean of its divisors is an integer number (4162511673756).

Almost surely, 211100031130014 is an apocalyptic number.

11100031130014 is a deficient number, since it is larger than the sum of its proper divisors (5550015565010).

11100031130014 is an equidigital number, since it uses as much as digits as its factorization.

11100031130014 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5550015565009.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 11100031130014 its reverse (41003113000111), we get a palindrome (52103144130125).

The spelling of 11100031130014 in words is "eleven trillion, one hundred billion, thirty-one million, one hundred thirty thousand, fourteen".

Divisors: 1 2 5550015565007 11100031130014