11100111283 has 2 divisors, whose sum is σ = 11100111284. Its totient is φ = 11100111282.

The previous prime is 11100111263. The next prime is 11100111331. The reversal of 11100111283 is 38211100111.

11100111283 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11100111283 - 2⁵ = 11100111251 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11100111283.

It is not a weakly prime, because it can be changed into another prime (11100111263) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550055641 + 5550055642.

It is an arithmetic number, because the mean of its divisors is an integer number (5550055642).

Almost surely, 2^11100111283 is an apocalyptic number.

11100111283 is a deficient number, since it is larger than the sum of its proper divisors (1).

11100111283 is an equidigital number, since it uses as much as digits as its factorization.

11100111283 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 11100111283 its reverse (38211100111), we get a palindrome (49311211394).

It can be divided in two parts, 11100111 and 283, that multiplied together give a palindrome (3141331413).

The spelling of 11100111283 in words is "eleven billion, one hundred million, one hundred eleven thousand, two hundred eighty-three".