111001133011 has 2 divisors, whose sum is σ = 111001133012. Its totient is φ = 111001133010.

The previous prime is 111001132961. The next prime is 111001133017. The reversal of 111001133011 is 110331100111.

It is a strong prime.

It is an emirp because it is prime and its reverse (110331100111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111001133011 - 2¹⁷ = 111001001939 is a prime.

It is a super-2 number, since 2×111001133011² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 111001132982 and 111001133000.

It is not a weakly prime, because it can be changed into another prime (111001133017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55500566505 + 55500566506.

It is an arithmetic number, because the mean of its divisors is an integer number (55500566506).

Almost surely, 2^111001133011 is an apocalyptic number.

111001133011 is a deficient number, since it is larger than the sum of its proper divisors (1).

111001133011 is an equidigital number, since it uses as much as digits as its factorization.

111001133011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 111001133011 its reverse (110331100111), we get a palindrome (221332233122).

The spelling of 111001133011 in words is "one hundred eleven billion, one million, one hundred thirty-three thousand, eleven".